A particle is moved along a path AB-BC-CD-DE-EF-FA, as shown in figure, in presence of a force ➝F=(????yî+2????xĴ)N,where x and y are in meter and ????= – 1 Nm⁻¹ . The work done on the particle by this force ➝F will be _______ Joule.
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Explanation:answer is 0.75
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Answer: Why to do all the Integration
Explanation: Just find the area of the Graph
Work done = area of (ABCDEFA)
area of (ABCDEFA) = area of (Big Square) - area of (Small Square)
= 1 - 0.25
= 0.75
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