A particle is moving along a circle such that is the complete one revolution in 40 second in 2 minute and 20 seconds the ratio of displacement and the distance is
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Hi! Devika,
Let ‘R’ be the radius of the circular path in meters.
2minutes 20 seconds [(2 60) +20] = 140 seconds
Distance covered in one revolution = 2πR meters.
Time for one revolution = 40s

Distance covered in 3.5 revolutions = 3.5 2πR meters =7πR meters
Displacement in 3.5 revolutions = 2R meters. ( Displacement is the least distance between initial and final positions).

Hopr it is clear to you!!
!
Let ‘R’ be the radius of the circular path in meters.
2minutes 20 seconds [(2 60) +20] = 140 seconds
Distance covered in one revolution = 2πR meters.
Time for one revolution = 40s

Distance covered in 3.5 revolutions = 3.5 2πR meters =7πR meters
Displacement in 3.5 revolutions = 2R meters. ( Displacement is the least distance between initial and final positions).

Hopr it is clear to you!!
!
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