A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio |displacement|/distance is
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Answered by
313
Radius of circular path= R
Time = 2 min20sec=140sec.
Distance covered in 1 sec = 2 π R
Time for one revolution =40sec
Revolution completed in 140 sec= 140/40=3.5
DISTANCE covered in 3.5 revolution =3.5×2 π R
=7 π R meters.
Displacement in 3.5 revolution =2R meter. ( Shortest distance between initial and final distance).
Ratio of displacement to distance:
2R/ 7πR
=2/7 π
Time = 2 min20sec=140sec.
Distance covered in 1 sec = 2 π R
Time for one revolution =40sec
Revolution completed in 140 sec= 140/40=3.5
DISTANCE covered in 3.5 revolution =3.5×2 π R
=7 π R meters.
Displacement in 3.5 revolution =2R meter. ( Shortest distance between initial and final distance).
Ratio of displacement to distance:
2R/ 7πR
=2/7 π
Answered by
39
Explanation:
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