Question

A particle is moving along a circular path of radius R with uniform speed a direction of velocity and acceleration of particles when it is at point P​

Answer 1

Answer:

v is velocity at a point then v is in the direction of tangent to the circular path at that point. When particle completes half the circle it reaches the diagonally opposite point where the direction of tangent is opposite. Hence, if we call velocity at first point as+v, it is-v at the other point. The difference or change =-v-(+v)=-2v.