A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is V_(0). Find the speed of the particle after time t=(R )//(2V_(0))
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Explanation:
integrate dt from 0 to r/2v.
v.=> v0
dv is integrated from v. to v
solve to get v
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