Question

A particle is moving along a circular path with a constant
speed of 10 ms. What is the magnitude of the change in
velocity of the particle, when it moves through an angle of
60° around the centre of the circle? (2019 Main, 11 Jan 1)
(a) 10/2 m/s
(b) 10 m/s
(c) 1043 m/s
(d) Zero
OA
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Answer 1

Answer:

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Explanation:

45

Answer 2

Answer:

(b)

Explanation:

Change in magnitude of velocity is given by = 2v sin(θ/2)

Here,

v = 10 m/s

θ = 60°

∴ Magnitude of change = 2(10)(sin 30°) = 10 m/s. (b.)

More:

• Displacement by a moving particle in a circular path is given by 2R sin(θ/2) where, R = radius of path.
• Distance covered by it = l = Rθ where θ is in radian measure and R = radius of path.