A particle is moving along a circular track of radius 10cm what is the distance traversed by the particle in two and a half revolution and find out resultant displacement
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Hey.
Here is the answer.
r=10cm
distance covered in one revolution= 2πr
=2π10= 20π cm
distance travelled in half revolution
= 20π/2=10π cm
so, distance travelled in 2 and half revolution
= 2×20π + 10π = 50π cm = 157.00 cm
the displacement = diameter of the circle = 2r
as displacement is the shortest path between initial and final position
=2×10 cm= 20 cm
Thanks.
Here is the answer.
r=10cm
distance covered in one revolution= 2πr
=2π10= 20π cm
distance travelled in half revolution
= 20π/2=10π cm
so, distance travelled in 2 and half revolution
= 2×20π + 10π = 50π cm = 157.00 cm
the displacement = diameter of the circle = 2r
as displacement is the shortest path between initial and final position
=2×10 cm= 20 cm
Thanks.
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