Question

A particle is moving along a coordinates line such that its position at any time T is given by X equal to cube of t minus 18 into t+ 11 find its speed velocity and acceleration when t equal to one

Answer 1

$according \: to \: question \\ x \: = t ^{3} - 18t + 11 \\ \frac{dx}{dt} = 3t { }^{2} - 18 \\ at \: t = 1 \\ velocity \: = \: - 15 \: which \: is \: impossible \: \\ and \: for \: acceleration \\ \frac{d {}^{2}x }{dt {}^{2} } = 6t \\ and \: at \: t \: = 1 \: accelartion \: is \\ \: \: \: \: + 6$
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