Question

A particle is moving along a straight line parallel to x axis with constant velocity find angular momentum about the origin in vector form

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Answer 1

$\huge\underline\mathfrak\blue{Answer}$

Option (2) -mvbk^

$\huge\underline\mathfrak\blue{Explanation}$

Here position vector ( r^ ) = bj^...(1)

Mass of the body = m

Velocity of the body ( V^ ) = vi^.....(2)

We know that,

Angular momentum = m(r^×V^)

From (1) and (2)

Angular momentum = m(bj^×vi^)

$\implies$ Angular momentum = -mbvk^

We must know :

• l × j = k

• j × i = -k

Hence, the correct option is 2) -mbvk^

Answer 2

Answer:

Option => 2.

$\implies - mb\;v\hat{k}$

Explanation:

Given :

A particle is moving along a straight line parellel to x -axis.

This statement implies,

$\implies \textbf{Position vector}=(\hat{r})=b\hat{j}$

Let the Mass of body be m.

Velocity of body - $\hat{V} = v \hat{i}$

Now,

We have to find angular momentum as given in question,

So,

We know that :

$\bigstar\;\boxed{\textbf{Angular Momentum}= m(\hat{r}\times\hat{V})}}$

Therefore,

$\implies m (b\hat{j} \times v \hat{I})\\ \\ \implies-mbv \hat{k}$

∴ Therefore, Option => 2 is the correct answer.

Edit : Here,

⇒ j × i = - k.

∵ I × j = k