Math, asked by Nandini2885, 1 year ago

...........answer.........

Attachments:

Answers

Answered by ajaykumar754006
1

Case1: S.P.= ₹63000

Gain=5%

Therefore,C.P.=

(SP × 100)÷(100+gain%)

=₹(63000×100)÷(100+5)

=₹1260000/23=₹54782.60


Case2: SP=₹63000

Loss= 10%

Therefore, CP= (SP×100)÷(100-loss%)

=₹(63000×100)÷(100-10)=₹70000


Total CP=₹(54,782.6+70,000)

=₹1,24,782.6

Total SP= ₹(63000×2)=₹1,26,000

Since SP is greater than CP,

Therefore, profit= SP-CP

= ₹(126000-124782.6)=₹1217.4{Ans}

Answered by Arsal843
1
5% loss on one buffalo
cost of one buffalo=63000
Formula=SP=100+profit%/100*CP
profit%=5%
CP=63000
100+5/100*63000=66150
profit=66150-63000=3150
10% profit on another buffalo
cost of one buffalo=63000
Formula=SP=100-loss%/100*CP
Loss%=10%
CP=63000
100-10/100*63000=56700
loss=63000-56700=3300
Total CP=63000*2=126000
Total SP=56700+66150=122850
SP<CP
it means that it is a loss.
loss=CP-SP
loss on both buffalo=3300-3150=150



Similar questions