A particle is moving along a straight line such that its position is given by :
x = t3 – 6t2+ 9t m, where t is in seconds. Determine the distance traveled during the first 2 seconds.
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Answer:
2m
Explanation:
Given
x= t^3 - 6t^2 + 9t ( t= 2 sec)
= (2^3) - 6(2^2) + 9(2)
= 8 - 24 + 18
= 2 m
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