A particle is moving along a straight line with constant acceleration a. Show that the average velocity of the particle during time 0-t is vavg = ( v+ u)/2.
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Answer:
0-t is vavg = ( v+ u)/2.
Explanation:
0-t is vavg = ( v+ u)/2.a) maximum in (i)
(b) maximum in (ii)
(c) maximum in (iii)
(d) same in all the cases
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