A particle is moving along a straight line with constant acceleration 8m/s². Find the change in velocity during the time interval t =1s to t=3s .Also calculate the displacement during this time interval to do with indefinite integration the information required as follows the initial displacement is 6 metre and initial velocity is minus 2 metre per second
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Explanation:
Calculate it with this formula
Sn=v+a/2(2n-1)
Where n=time given
V=velocity
a=acceleration
Sn=distance
So when two values are given ie(example 15m in 6sec. and 21m in 8 sec) then put individually in the formula and then subtract their equations from one another. You get the required values
If I made mistake then point out me... That I can correct my mistakes
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