A particle is moving along east direction with
a velocity 9 m/s in a time 3 sec, same particle
is moving along north direction with a velocity
16 m/s, in time 4 sec from the same point.
Find the resultant acceleration , resultant velocity
vector form of acceleration
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Answer:
Explanation:
Intial velocity=v1=5m/seast wards
then after time t=10sec
v2=5m/s north wards
δv=
V
1
2
+
V
2
2
=
25
+25
=5
2
acceleration a=
time
velocity
=
10
5
2
=
2 2 × 2 2
=
2 1
towards n-w
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