Question

A particle is moving along is direction with a speed of 5 metre per second... after 10 seconds it deviates towards north with the same speed find average acceleration of the particle

Answer 1

Allright.

If we take the x axis to represent “East” direction, and the y axis “North”, then

V(initial) = 5i m/sec,

V(final) = 5j m/sec,

i and j being respective unit vectors,

Then

a = (V(final)-V(inital))/t = (5j - 5i)/10 m/sec*sec = (1/2j - 1/2i)m/sec*sec

If you want the scalar of a then:

|a| = sqrt(1/2*1/2*i*i + 1/2*1/2*j*j) m/sec*sec = 1/sqrt(2) m/sec*sec

The direction should be N.W.