Question

a particle is moving along north after moving for 2 seconds with the speed of 4m/s it's speed becomes 5 m/s what is its displacement at end of 7 seconds​

Answer 1

Explanation:

Case 1

t1=2s

v1=4m/s

We know, Displacement=Velocity*Time

therefore, D1=4*2=8m

Case 2

t2=7s-2s(because for initial 2s it was travelling with different speed)=5s

v2=5m/s

d2=5*5=25m

total dispacement=d1+d2=8+25=33m