Question

a particle is moving along positive x-axis with constant acceleration of 3 ms2. it is at x = 0 m at time t = 0 s and it has velocity 15 ms1, then its position at t = 6 s will be

Answer 1

According to question the data which are given is a = 0.5 m/s2, u =0 at t =0 , 

hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)

using equation of motion 

v = u+at

v = 0+0.5 x5 = 2.5 m/s.

now the displacement at the end of 5 second is 

s = ut +0.5 at2

s = 0+ 0.5 x  0.5 x 52

   = 6.25 metre..

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