A particle is moving along x axis and its position varies with time as x=2t3 -3t2 +1. At what time velocity will be zero? Also find what is the velocity when it passes the origin.
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Answer:
Given that,
x=10t−2t2
so,
v= dt /dx
=10−4t
The particle will come to rest if v = 0
10−4t=0
t=2.5s
Explanation:
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