Question

A particle is moving along x-axis. At time t1 = 3s, its position is x1 = 40.5 m and at time t2 = 5.5s its position is x2 = 18.2 m. What is its displacement?

Answer 1

Answer:

The average velocity of the particle is the ratio between the displacement and the time.

v

avg

=

t

2

−t

1

x

2

−x

1

or, v

avg

=

7−2

18−3

or, v

avg

=3m/s is our required answer.