Question

a particle is moving along x axis whose instantaneous speed is given by
${v}^{2} = 108 - {9}^{2}$
Find the acceleration...​

Answer 1

Answer:

ANSWER

v

2

=108−9x

2

2v

dx

dv

=−18x

As we know a=

dx

dv

dx

dx

=

dx

dv

dt

dx

=v

dx

dv

So, a=−18xm/s

2

.

Answer 2

Answer:

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