Physics, asked by IITIANHARSH, 1 year ago

A particle is moving around a circle of radius R equals to 1.5 metre with a constant speed of 2 metre seconds what is the centripetal acceleration the angular velocity of the particular

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Answered by Sb59
17

Hope that this will be enough.

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Answered by rinayjainsl
3

Answer:

The centripetal acceleration and angular velocity of the particle are 2.67m/s^{2} and 1.33rad/sec respectively.

Explanation:

Given that,

A particle is moving around a circle of radius 1.5m with a constant speed of 2m/s.We are required to find its centripetal acceleration and angular velocity.

The centripetal acceleration of an body moving along a circular path is the ratio of square of its velocity and radius of path.Hence,

a_{c}=\frac{v^{2}}{r}

Substituting the known values in above relation,we get

a_{c}=\frac{2^{2}}{1.5} =2.67m/s^{2}

Also the angular velocity of a body moving along circular path is teh ratio of its linear velocity and radius.Hence,

\omega=\frac{v}{r}

Substituting the values,we get

\omega=\frac{2}{1.5}=1.33rad/sec

Therefore,the centripetal acceleration and angular velocity of the particle are 2.67m/s^{2} and 1.33rad/sec respectively.

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