Question

A particle is moving eastward with a velocity of 15m/s. in a time of 10s

Answer 1

Answer:

Explanation:

Remember that velocities Vf and Vi are vectors, so direction is important.

a=ΔV¯Δt=V¯f−V¯iΔt

An easy way to subtract a vector is to add the negative vector where the negative vector is the same magnitude but going in the opposite direction. So Vf−V¯i is the same as Vf+(−V¯i):

If Vi=Vf=5ms

then 52+52=(Vf−Vi)2

Vf−Vi=7.071ms

a=ΔV¯Δt=7.071ms10sec=0.707ms2 at an angle 45∘

Answer 2

we get answer :-

15√2

avg. = -------------

10

= 3/√2 (NW)