A particle is moving eastward with a velocity of 5m/s in 10s the velocity changes to 5m/s
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Initial velocity, u=5m/s eastwards
Final velocity, v=5m/s northwards
Now, change in the velocity ∣△v∣=
v
2
+u
2
=
5
2
+5
2
=5
2
And the direction of △v is given by
tanθ=
u
v
=
5
−5
=−1 (taking east direction as positive)
θ=−
4
π
Now, acceleration a=
t
△v
=
10
5
2
=
2
1
m/s
2
in north-west direction.
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