Question

ab is a diameter of a circle with centre o . if ade and cbe are straight lines meeting at e such that angle bad = 35 and angle bed = 25 degree find angle dbc , angle dcb and angle bdc

Answer 1

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Answer 2

Hey dude


Your answer is here ☺️☺️



Given:- AB is a diameter of a circle with Centre
O. ADE and CBE are straight lines.
Angle BAD =35 °, angle BED =25 °


R. T. F:- angle DBC
Angle BDC
Angle DCB

Solution:- angle BCD = angle BAD [angles in
The same segment are equal]

Angle BCD=35°

In triangle ABE,

Angle ABC = angle BAE + angle
BEA
[exterior angle = sum of interior
angle]

Angle ABC =35°+25°=60°

IN triangle ABD, angle ABD = 180°-
( BAD + BDA)
180°-(35°+90°)

[ angle BDA =90°, since AB is a
diameter]

Angle ABD =180°-125°=55°

Angle CBD = angle ABC + angle
ABD
60°+55°=115°

In triangle BDC, angle BDC =180°-(
BCD + CBD)

180°-(35°+115°)
180°-15°
30°

Thank you ☺️☺️☺️❤️❤️❤️