Question

A particle is moving in a circle of diameter 14 m. calculate the distance covered and the displacement when it completes 3 revolutions.

Answer 1

radius=14/2=7 m.
distance travelled in 3 revolutions=3*the perimeter of the circle=3*pi*radius=3*22/7*7=66m
dispacement=0

Answer 2

Answer:

The distance and displacement of particle after 3 revolutions are 132m and 0m respectively

Explanation:

Given that,

A particle is moving in a circle if Diameter 14m

Therefore,the radius of the circle is

$r = \frac{d}{2} = \frac{14}{2} = 7 \: m$

Distance covered per revolution is nothing but the circumference of the circle.The circumference of the circle is found as

$C=2πr$

Substituting the known values,we get

$C=2 \times \frac{22}{7} \times 7 \\ = 44 \: m$

This is distance for one revolution.Therefore,the distance covered for 3 revolutions is

$3 \times 44 = 132 \: m$

As the the particle returns to its initial position for each revolution,hence its displacement after completing 3 revolutions is zero.

Therefore,The distance and displacement of particle after 3 revolutions are 132m and 0m respectively

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