Physics, asked by Srivalle, 1 year ago

A particle is moving in a circle of radius R with constant speed V then changing velocity after the particle has travelled a distance equal to 1 by 8 of the circumference of the circle is

Answers

Answered by mahendrachoudhary123
6
angle =360/8=45 degree
delta V=rootof(v^2+v^2-2*v^2*1/rootof2)
= ...........(2v^2-root2*v^2)
= v*rootof(2-root2)
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