Question

A particle is moving in a circular path of radius r the displacement after half a circle whould be be

Answer 1

GIVEN :-

• A particle is moving in a circular path of radius r.

TO FIND :-

• The displacement after half a circle.

SOLUTION :-

$\setlength{\unitlength}{1mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(25,30){\line(5,0){20}}\put(25,30){\circle*{1}}\put(29,26){\sf\large{r }}\end{picture}$

$\rule{160}{1}$

DISPLACEMENT:-

▪︎As we know that displacement is total distance covered by an object from his initial position to final position.

▪︎As the object covered half of the circular path then he covered the displacement r + r = 2r.

▪︎Hence the displacement of the particle is 2r.

DISTANCE :-

▪︎Distance is total distance covered by an object.

▪︎As the object covered half of the circle then Distance = 1/2*2π×r = π r

▪︎Hence the distance Will be πr