A particle is moving in a circular path of radius R, then then displacement of the particle after it covers one third of the circle is?
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When particle moves along half circle, it covers half the circumstance therefore distance covered is (2×pi×r)/2 = pi× r. Where r is radius of circle. It is diametrically opposite to the starting point of its motion. Therefore shortest distance is equal to diameter of circle or 2× r is a displacement
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