Question

A particle is moving in a straight line and at some moment it occupied the positions (5,2) and (-1,-2). Then the position of the particle when it is on x-axis is
A) (-2,0) B) (0, 2) C) (2,0) D) (4, 0)






Pls answer as fast as possible.....​

Answer 1

Step-by-step explanation:

from above point we can see

change in x axis by -1-5=-6 unit

change in y axis by -2-2=-4unit

Then the position of the particle when it is on x-axis is = [{5-(6/2)},{2-(4/2)}]= {(5-3),(2-2)}=(2,0)

Answer 2

The position of the particle when it is on x-axis is (2,0)

Given :

A particle is moving in a straight line and at some moment it occupied the positions (5,2) and (-1,-2)

To find :

The position of the particle when it is on x-axis is

A) (-2,0)

B) (0, 2)

C) (2,0)

D) (4, 0)

Solution :

Step 1 of 2 :

Find the equation of the line

Here it is given that the particle is moving in a straight line and at some moment it occupied the positions (5,2) and (-1,-2)

The equation of the line is

$\displaystyle \sf{ \frac{y - 2}{x - 5} = \frac{2 - ( - 2)}{5 - ( - 1)} }$

$\displaystyle \sf{ \implies \frac{y - 2}{x - 5} = \frac{2 + 2}{5 + 1} }$

$\displaystyle \sf{ \implies \frac{y - 2}{x - 5} = \frac{4}{6} }$

$\displaystyle \sf{ \implies \frac{y - 2}{x - 5} = \frac{2}{3} }$

$\displaystyle \sf{ \implies 2x - 10 = 3y - 6 }$

$\displaystyle \sf{ \implies 2x - 3y = 4 } \: \: \: \: - - - - (1)$

Step 2 of 2 :

Find the position of the particle when it is on x-axis

Since the particle is on x axis

We have y = 0

Putting y = 0 in Equation 1 we get

$\displaystyle \sf{ 2x = 4 }$

$\displaystyle \sf{ \implies x = 2 }$

So the position of the particle when it is on x-axis is (2,0)

Hence the correct option is C) (2,0)