In a two-digit number, the digit in the tens place is three times the digit in the units
place. If the sum of the digits is 9, find the number,
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Answered by
1
Step-by-step explanation:
Number is 62. So number is 10*3*2+2=62.
Answered by
1
Step-by-step explanation:
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 3x.
Hence, the 2-digit number = 31 x = 31 × 2 = 62 31x=31\times2=62
31x=31×2=62.
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