Physics, asked by singhchandrajeet294, 10 months ago

a particle is moving in a straight line with initial velocity 10ms and acceleration -4ms^-2 .Then find distance coverd during 3rd second .

Answers

Answered by aryan1234243

0

Answer:

s=10x3+1/2x-4x9

s=30+-18

s=30-18

s=12

Answered by nagaisiva80

0

Explanation:

the above attachment has the answer

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