Question

A particle is moving in a three dimensional potential v(x y z)=1/2mw^2

Answer 1

Explanation:

Along x-axis as a function of time .The acceleration of the particle is zero in the region :

Displacement

Timeparticle in moving in a three dimensions potential v(x)=1/2mw^2 (2x^2+y^2+4y^2)

If the mass of particle is m