a particle is moving in x-y plane the coordinate of particle is given by x=5t^2 and y=10t. find velocity at t= 1s.Also find acceleration at t=1s
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Answer:
Problem solved
A particle move along a straight line. The velocity of the particle is given by v(t)= t^3 +4t² +6t=7, and the position of the…
Explanation:
x=5t−2t
2
y=10t
dt
dx
=5−4t
a
x
=
dt
2
d
2
x
=−4
a
y
=
dt
2
d
2
y
=0
a=a
x
+a
y
=−4+0
a=−4 ms
2
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