Physics, asked by shreyakumari8102003, 3 months ago

a particle is moving in x-y plane the coordinate of particle is given by x=5t^2 and y=10t. find velocity at t= 1s.Also find acceleration at t=1s​

Answers

Answered by itzHATERxx
1

Answer:

Problem solved

A particle move along a straight line. The velocity of the particle is given by v(t)= t^3 +4t² +6t=7, and the position of the…

Explanation:

x=5t−2t

2

y=10t

dt

dx

=5−4t

a

x

=

dt

2

d

2

x

=−4

a

y

=

dt

2

d

2

y

=0

a=a

x

+a

y

=−4+0

a=−4 ms

2

Similar questions