Question

A particle is moving in xy plane. Its position vector is: r = 2ti+3t² m. Find:
1.equation of velocity.
2.equation of acceleration.
3.magnitude of velocity and acceleration at t=2s.​

Answer 1

Explanation:

(a)

v

(t)=d

r

/dt

=3.0

i

^

−4.0t

j

^

a

(t)=d

v

(t)/dt

=−4.0

j

^

(b)

v

(2)=3.0

i

^

−8.0

j

^

v(2)=8.54m/s

∠v(2)=tan

−1

(−8/3)=−69.44

∘

with x axis