how will you convert 2-chloropropane into propan-2-ol
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CH3–CH–CH3–——>(hot and acl) CH3— CH=CH2
/Cl
( 2- chloropropane)
1) B2H6
——-—>CH3 — CH2 ———> CH2OH
2) H2O2 /OH-
Explanation:
The mechanism of the reaction involves the following 3 steps :
1) Proptanation of ethene to form carbocation by electrophilic attack of H3O+.
2) Nucleophilic attack of water on carbocation
3) Deprotonation to form an ethanol
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