Question

two vectors are given by a is equals to minus 2 ICAP + 2 J cap - 3 k cap and vector b is equals to 5 ICAP + 3 J cap - 2 k cap if 3 A + 2 b minus C is equal to zero then third vector C is ​

Answer 1

Explanation:

hope this will help you..

Answer 2

Given:

a = -2i + 2j - 3k

b = 5i + 3j - 2k

and,

3a + 2b - c = 0

To Find:

vector c?

Solution:

As given,

a = -2i + 2j - 3k

b = 5i + 3j - 2k

and,

3a + 2b - c = 0

put value of a and b in above equation,

3.( -2i + 2j - 3k ) + 2. ( 5i + 3j - 2k ) - c = 0

⇒ -6i + 6j -9k + 10i + 6j - 4k = c

⇒ 4i + 12j - 13k = c

Hence, the vector c is  4i + 12j - 13k.