A particle is moving on a circular path of 10m radius. At any instant of time its speed is 5ms-1 and the speed is increasing at a rate of 2ms-2. The magnitude of net acceleration at this instant is ? A particle is moving on a circular path of 10m radius. At any instant of time its speed is 5ms-1 and the speed is increasing at a rate of 2ms-2. The magnitude of net acceleration at this instant is ?
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Answered by
50
Net Acceleration is the resultant acceleration of centripetal acceleration and tangential acceleration thus find both of them as follows
Ac - be centripetal acceleration.
At - be tangential acceleration.
Anet =√(Ac² + At²)
now then -----
Ac is = V²/R = 25/10 = 2.5 m/s².
At is given as 2 m/s². thus
Anet comes out on calculating as
= 3.20 m/s².
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Ac - be centripetal acceleration.
At - be tangential acceleration.
Anet =√(Ac² + At²)
now then -----
Ac is = V²/R = 25/10 = 2.5 m/s².
At is given as 2 m/s². thus
Anet comes out on calculating as
= 3.20 m/s².
✨✨✨✨✨✨✨✨✨✨✨✨
Answered by
2
3.2 ms-2 be the magnitude of net acceleration at this instant
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