Question

A particle is moving on a circular path of radius 10 m with uniform speed of 4m/s .the magnitude of change in velocity of particle when it completes a semi-circular path is

Answer 1

When it completes semicircular path it’s velocity direction will be exactly opposite to that of initial.

So,

Change in velocity = v - (-v) = 2v = 2 × 4 m/s = 8 m/s

#Be Brainly❤️