Question

A particle is moving on a circular path of radius 1m. It starts from rest. Its tangential
acceleration is √3t. The time after which the acceleration of the particle makes an angle of 30°
with centripetal acceleration is (n^2/3) s. Then the value of n is​

Answer 1

Answer:

n value is 2

Explanation:

given acceleration vector is at 30 degrees to centripetal acceleration

so we take components of tangential and centripetal we get

tan 30 = A t / A c A t is tangential acceleration

A c is centripetal acceleration

tan 30 = 1/ root 3

1/ root 3 = root 3 ×t/A c , A t = root 3 ×t

so we get A c = 3t

the further is in attachment

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