Question

A particle is moving on a circular path with constant speed v . what is the change in its velocity after it has described an angel of 60°

Answer 1

first if velocity is directed upwards. then initial velocity vector is v i + 0 j. as it makes a angle of 60 degrees then velocity vector is v(cos60) i + v(sin60) j. change in velocity is (v/2 i + √3/2v j )- v i=-v/2 i + √3/2v j .