Question

A particle is moving on a straight line along x -direction.A graph between square of its velocity & position is drawn as shown.Find the magnitude of acceleration (in m/s^(2) ) of particle​

Answer 1

Answer:

v

2

=2as+u

2

y=mx+c

m=2a

a=

2

m

Slope m ca be calculated as

m=

x

2

−x

1

y

2

−y

1

=

0.6−0

900−3600

=−

0.6

2700

∴a=−

2

m

=−

2

4500

=−2250km/hr

2

Answered By

toppr

Explanation:

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