A particle is moving on a straight line along x -direction.A graph between square of its velocity & position is drawn as shown.Find the magnitude of acceleration (in m/s^(2) ) of particle
Answers
Answered by
0
Answer:
v
2
=2as+u
2
y=mx+c
m=2a
a=
2
m
Slope m ca be calculated as
m=
x
2
−x
1
y
2
−y
1
=
0.6−0
900−3600
=−
0.6
2700
∴a=−
2
m
=−
2
4500
=−2250km/hr
2
Answered By
toppr
Explanation:
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