Question

The ten’s digit of a 2-digit number is 2 times its ones digit. If the digits are reversed,

The sum of the original number & the number so formed is 66. Find the number.
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Answer 1

♤Answer♤

Let the number be “xy”, which values (10x+y).

Given, x = 2y.

When it is reversed, it becomes “yx”, which values (10y+x).

Also, (10x + y) + (10y + x) = 66

11(x + y) = 66

(x + y) = 6

(2y + y) = 6

y = 2

x = 4

Original number = 42.

Answer 2

Answer:

The answer to your question is 42

Hope it helps!!!