Question

A particle is moving on a straight line along
x-direction. A graph between square of its
velocity Ne position is drawn as shown. Vind
the magnitude of acceleration in m/s) of
particle​

Answer 1

Answer:

average velocity is 25m/s so distance will be 25×20=500m

now finding area of the graph between velocity and time graph we get

area of two triangles + area of rectangle.

2.

2

1

t.5.t+(25−2t).5t=500=>t

2

−25t+100

=>t=5

so option B is answer.

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Answer 2

Answer:

1/2*100*25

= 50*25

=750