A particle is moving uniformly in a circular path of radius r. What is the magnitude of its change in velocity if it moves through an angular displacement theta.
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Answer:
The particle starts from point P and reaches at R after moving an angular displacement of θ.
∴ The linear displacement of the particle s=PR
From the geometry, PQ=r sin(
2
θ
)
∴ s=2PQ=2r sin(
2
θ
) (∵PQ=
2
1
PR)
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