Question

A particle is moving westward with a velocity v =5m/s. Its velocity changed to V2 = 5m/s
northward. The change in velocity vector (ΔV = V2-V1) is:
(A) 5/2 m/s towards north east
(B) 5 m/s towards north west
(C) zero
(D) 5.2 m/s towards north west​

Answer 1

Answer:

(A) 5 root(2) m/s towards north east

Explanation:

Magnitude by (5²+5²)^1/2 = 5 (2)^1/2 {5 root 2}

Direction by adding v2 and (-v1)

Answer 2

Given:

• Initial Velocity ($V_1$) = $5ms^{-1}$

• Final velocity($V_2$) = $5ms^{-1}$  

To Find:

• The Change in Velocity (ΔV)

Solution:

• We are finding the velocity change by using the formula,
• ΔV = $V_2-V_1$
• ΔV = 5-5
• ΔV = 0
• This implies that the velocity is the same in any direction and the magnitude of the direction is zero.
• The answer is zero because the initial velocity and final velocity are in the same direction and travel in the same path,
• so we can even say that the magnitude is also zero.

Change in Velocity(ΔV) = 0