Question

A particle is moving with 5m/s and accelerated uniformly with 2m/s2 for 10s find displacement in the last 1sec.

Answer 1

Answer:

24 m

Explanation:

According to the given question,

u = intital velocity = 5 m/s

a = acceleration = 2 m/s^2

t = time = 10 sec

And we are asked to find the displacement of the particle in the last 1 sec.

We know,

Displacement in last 1 sec = Displacement of 10 sec - Displacement of 9 sec

Thus, from the 2nd formula of accelerated motion,

• s = ut + 1/2 at^2

(For 10 sec)

Putting the values we get,

• s" = 5×10 + 1/2 × 2 × 100

• s" = 50 + 100

• s" = 150 m

Where s" is the displacement of the particle of 10 sec.

Again,

(For 9 sec)

• s' = 5×9 + 1/2 × 2 × 81

• s' = 45 + 81

• s' = 126 m

Where s' is the displacement of particle of 9 sec.

Now,

• s = s" - s'

• s = 150 - 126

• s = 24 m

Where, s = required displacement or displacement of the particle in last 1 sec.

Answer 2

ANSWER:

displacement in last 1 second = 24 m

Explanation:

given that,

A particle is moving with 5m/s and accelerated uniformly with 2m/s² for 10s find displacement in the last 1sec.

so,

here we have,

initial velocity of the particle = 5 m/s

acceleration produced by the particle =

2 m/s²

time taken for accelerating = 10 s

now,

we have,

initial velocity(u) = 5 m/s

acceleration(a) = 2 m/s²

time taken(t) = 10 s

let the distance be s

so,

by the equation of motion

s = ut + 1/2(at²)

putting the values,

s = (5)(10) + 1/2(2)(10)²

s = 50 + 200/2

s = 50 + 100

s = 150 m

so,

displacement in 10 seconds =

150 m

now,

to find

displacement in last 1 seconds

displacement in last 1 seconds = displacement in 10 seconds - displacement in 9 seconds

now,

we have,

initial velocity(u) = 5 m/s

acceleration(a) = 2 m/s²

time taken(t) = 10 seconds

let the final velocity be v

so,

by the equation of motion

v = u + at

putting the values

v = 5 + 2(10)

v = 5 + 20

v = 25

now,

time = 9 seconds,

by the equation of motion,

s = ut + 1/2(at²)

putting the values for 9 seconds,

s = 5(9) + 1/2(2)(9²)

s = 45 + 81

s = 126 m

now,

we have,

displacenent in 10 seconds = 150 m

displacement in 9 seconds = 126 m

we know that,

displacement in last last 1 seconds = displacement in 10 seconds - displacement in.9bseconds

putting the values

150 m - 126 m

= 24 m

so,

displacement in last 1 second

= 24 m