Question

A particle is moving with a constant speed in a circular path. Find the ratio of average velocity to its instantaneous velocity when the particle rotates an angle theta =((pi)/(2)) .

Answer 1

Explanation:

The particle is moving with constant speed in CIRCULATION

therefore, its velocity would be zero

as it returns to its original position

So, ratio is also ZERO

0/x is always zero

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Answer 2

The ratio of average velocity to its instantaneous velocity is v  avg  / v = 2√2 /  π

Explanation:

Let the particle is moving with constant speed v and it reaches the point B in time t

Displacement D = AB = √ 2  r

Average velocity v(avg)  =  D /t =  t 2  r     -----------(1)

Using S = wt+  1/2  αt^2

Where α = 0

π/2  =  vt/r

v = πr  /  2t       ---------(2)

Dividing (1) and (2) we get

v  avg  / v =  √2r/t / πr /  2t

v  avg  / v = 2√2 /  π

Hence the ratio of average velocity to its instantaneous velocity is v  avg  / v = 2√2 /  π

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