Question

A particle is moving with initial velocity I m/s and acceleration a Find velocity Of particle at t 2 sec

Answer 1

ANSWER

The distance travelled in nth second is

Sn=u+21(2n−1)a          ....(1)

So distance travelled in tth&(t+1)th second are

St=u+21(2t−1)a          ....(2)

St+1=u+21(2t+1)a      ....(3)

As per question,

St+St+1=100=2(u+at)         ....(4)

Now from first equation of motion the velocity of particle after time t, if it moves with an acceleration a is

v=u+at              ....(5)

where u is initial velocity

So from equation (4) and (5), we get v=50cm/s