Diagram DE is parallel to BC,AE=3cm ,CE=6cm,AD=4cm then find the length of AB
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Answer:
Length of AB = 12 cm
Given that
DE||BC
AE = 3 cm
CE= 6 cm
AD= 4 cm
From the figure
DE || BC , thus
Δ ADE ≅ ΔABC
⇒ \frac{AD}{AB} = \frac{AE}{AC}
AB
AD
=
AC
AE
Put all the values from the figure we get
⇒ \frac{4}{4 + x} = \frac{3}{9}
4+x
4
=
9
3
⇒ 36 = 12 + 3 x
⇒ 3 x = 24
⇒ x = 8 cm
⇒ Length of AB = 4 + x
⇒ Length of AB = 4 + 8 = 12 cm
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