Question

Let 'm' be the L.C.M.
of 32002-1 & 32002+1.
Then the last digit of
'm' is​

Answer 1

The two numbers are 32002 - 1 and 32002 + 1,

i.e., 32001 and 32003

We have to find LCM of 32001 and 32003:

• We must know that 32003 is a prime number, but 32001 is not a prime number.
• To find the LCM of a prime number and a non-prime number, we find their product.

Therefore the required LCM is

= 32001 × 32003

= 1,024,128,003

Given, 'm' is the LCM of 32001 and 32003,

i.e., m = 1,024,128,003

Therefore the last digit of 'm' is 3.

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